Half of me!!

Level pending

When I was 2 years old, my sis was half of my age. Now I am 18 years old, what is the age of my sis?


The answer is 17.

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3 solutions

Eduardo Petry
Dec 31, 2013

Your sis age when you were two = 2 2 = 1 \displaystyle=\dfrac{2}{2}=1 . The difference of ages is 2 1 = 1 \displaystyle2-1=1 .

If you are 18 \displaystyle18 , your sis is 18 1 = 17 \displaystyle18-1=\boxed{17}

but it's must be half of it

Shubham Chaudhary - 7 years, 5 months ago

why is it happen that the ans. is 17 in this problem?
I think in law of proportion in math the solution must like this

formula:

a/b=c/d or a:b=c:d

sol'n

2/1=18/Y then cross multiply

2xY=18x1 then simplify

2Y=18

Y=18/2

Y=9

Karren Barrameda - 7 years, 5 months ago

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Vasavi's sis was half her age only when Vasavi was 2 \displaystyle2 years old. So the difference of ages is of 1 \displaystyle1 year. It's not really proportional, you see?

Eduardo Petry - 7 years, 5 months ago
Prasun Biswas
Feb 13, 2014

When she was 2 2 years old, her sister was half of her age, i.e, 2 2 = 1 \frac{2}{2}=1 years old.

After 16 16 years. she becomes 18 18 years old, so her sister's age should be = ( 1 + 16 ) = 17 years old =(1+16)=\boxed{17 \text{ years old }}

Sanghamitra Anand
Feb 12, 2014

Half of 2 is 1. So, her sister was 1 year old and 1 year younger than her. Therefore, when she is 18 years old, her sister must be 17!

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