Hang That Poster Properly

by drawing graph we get (4,8) the 4th coordinate.

This is the solution image

line intersecting from 4,2 and 7,8 makes the co ordinates 4,8 and it forms a rectangle so 4+8 = 12

(4,2) is the first coordinate,(7,2) & (7,8) are the 2nd & 3rd coordinate respectively,last coordinate must be(4,8) since it is a rectangle.(x,y)=(4,8)=12

just by drawing the graph and you''ll get the coordinates..

Graphically If we do it, we get it X co-ordinate 4 and Y Co-ordinate 8 which will create rectangle precisely. Hence it clearly implies a value of X+Y is equal to 4+8=12.

(4,8) = 12.

using graph, we can solve this.. by plotting the given co-ordinates

the all 4 points of rectangular ar at the right positive side ,so the remaning point is complimentry to the other 3 points ,the remaning point is (x,y)=(8+4)=12.

8+4=12

1ST COORDINATE IS (4,2) 2ND IS (7,2) 3RD ONE IS (7,8) THEN 4RT ONE IS (4,8) AND 4+8=12

By logic, if I'm joining the values of (4.2) and (7.8), the progression appears in (7.2) therefore only be wanting (4.8) that when added result 12

the picture is 3 units long and 8 unit high so the other co-ordinate will be (4,8) so x+y=4+8=12.

The answer is a simple pattern. The right digit was 4,8,4, so the next one is 8. The left digit was 4,7,7, so the next was most likely 4. 4+8=12.

one vertex is at (4,2) and near to it is (7,2). above (7,2) is vertex (7,8)..... so above (4,2) will be vertex (4,8) and hence (x,y)=(4,8) and x+y=4+8=12

just draw the rectangle you can find the co-ordinates for the fourth point and then just add those

4+8 =12

4 + 8 = 12

(7,8) e (7,2) tem mesmo X(a semirreta que as une, portanto é paralela ao eixo Y) e Y que varia de 2 a 8 . Para formar um retângulo o ponto(x,y) deve formar , com o ponto (4,2), uma semirreta paralela ao eixo Y (ou seja, com o mesmo X que esse ponto) , a semirreta também deve ter Y que varia de 2 a 8, portanto o ponto é (4,8)