Happy birthday Pranjal

Calculus Level 2

log 10 ( i = 1 1 0 9 cos ( lim x 17 x 2016 + 01 x 2015 + 2016 x 17012016 ) ) \log_{10}\left(\sum_{i=1}^{10^9} \cos \left(\lim \limits_{x \to \infty} \frac{17x^{2016}+01x^{2015}+2016}{x^{17012016}}\right)\right)

Evaluate the expression above.


This question is dedicated to Pranjal Jain


The answer is 9.

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1 solution

Jat In
Jan 18, 2016

putting first limit we get cos0=1 and adding 1 upto 10^9 times taking log we get 9

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