An algebra problem by samuel ayinde

Given:

$\frac{(2014-1997)^{2}}{17}=\frac{17^{2}}{17}=17$

Thus, the answer is $\boxed{17}$

$\frac{(2014-1997)^{2}}{(17)}$

= $\frac{(17^2)}{(17)}$

= $17$

$\qquad \frac { { (2014-1997) }^{ 2 } }{ 17 } \\ =\quad \frac { { (17) }^{ 2 } }{ 17 } \quad =\quad { 17 }^{ 2 }\times { 17 }^{ -1 }\\ =\quad { 17 }^{ 2-1 }\quad =\quad \boxed { 17 }$

We can also write (2014-1997)^2 as (2014-1997)(2014-1997)=17 * 17. Hence,we get 17*17/17=17.

(17*17)/17 =17

Hello,

Happy 17th birthday....

:)

$\frac{17^2}{17}=17$

$2014 - 1997 = 17$ .
Sp, $\dfrac{{(17)}^2}{17} = \color{#69047E}{\boxed{17}}$ .

(2014-1997)^2/17 = 0 then (2014-1997)^2 = 17. Then 2014-1997 = log17 17 = log17 17^2 = 17. Then divide it 17^2/17 =0 17 is the answer