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Calculus Level 4

χ ( y ) = { + 1 if y 1 ( m o d 4 ) 1 if y 3 ( m o d 4 ) {\chi \left( y \right) =\begin{cases} +1\quad \text{ if}\quad y\equiv 1 \pmod 4 \\ -1\quad \text{if}\quad y\equiv 3 \pmod 4 \end{cases}}

Define χ ( y ) \chi \left( y \right) as shown above. If the value of

p is prime , p 3 p 2 p 2 ( χ ( p ) ) 2 \large{\prod _{ \text{p is prime}, p\ge 3 }^{ }{ \frac { { p }^{ 2 } }{ { p }^{ 2 }-{ \left( \chi \left( p \right) \right) }^{ 2 } } } }

can be expressed as

A π B C \large{\frac { A{ \pi }^{ B } }{ C } }

for some positive integers A , B , C A,B,C such that A A and C C are coprime. Find the value of ( A + B ) × C (A+B) \times C .


The answer is 24.

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1 solution

Isaac Buckley
Jan 15, 2016

Notice that χ ( p ) 2 = 1 \chi(p)^2=1 for all prime p p so we can simply the above expression to:

p 2 1 1 1 p 2 = 3 4 ζ ( 2 ) = π 2 8 \Large \prod_{p\neq 2} \frac{1}{1-\frac{1}{p^2}}=\frac{3}{4}\zeta(2)=\frac{\pi^2}{8}

It would be helpful to others (beginners) if you include the reference to Euler product which is the main thing used in the solution.

Prasun Biswas - 5 years, 5 months ago

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