Happy ending

Find the number of three digit positive integers that any permutation of the digits of the number (which is another integer, with possibly three, two or one digits) is in the same equivalence class, modulo $7$ . So, if the number $x$ is a three digit positive integer and $y$ is a permutation of digits of $x$ , then $x\equiv y \ mod \ 7$ .

Note that the number itself should be a three digit number but its permutations can have a zero or two zeros at front.