Happy New Year!

Find the minimum exponent k k , so that the decimal notation 2 k 2^k contains 2020 inside.


The answer is 348.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Using python:

k=1

while "2020" not in str(pow(2,k)):

k+=1

print(k)

It will show "348"

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...