Happy New Year!

The first term of a sequence is 2014. Each succeeding term is the sum of the cubes of the digits of the previous term. What is the 2015th term of the sequence?

Share this problem if you like it!


The answer is 370.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Ratnadip Kuri
Jan 16, 2015

step 1: second term = 2 3 2^3 + 0 3 0^3 + 1 3 1^3 + 4 3 4^3 = 73

step 2: Third term = 7 3 7^3 + 3 3 3^3 =370

In third term non-zero digits are 3 and 7 which is same with second term. So 370 always return result 370. It doesn't matter what successive position of the number in the sequence. So, 2015th term is also 370.

Sudoku Subbu
Jan 16, 2015

when we go to the second term its 8+0+1+64=73 , the third term is 343 + 27=370 , again fourth , fifth , sixth , . . . . . . . . . . . . . . . . . 2015th term are 370 therefore the 2015th term is 370

Correct reasoning!

Ganeshkumar Ashokavardhanan - 6 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...