HAPPY NUMBER
Let call a number x of n digits to be a happy number if x^{k} has it last n digits same as the number x for any k (k is a natural number ). Also there exist some smallest p such that 2^{p} has it last n digits same as the number x. (where p varies with n). If for some fixed n, p/n=125, then find p+x for that fixed n.
The answer is 9876.
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