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1 solution
Let h and w be the present ages of Mr. Jorkins and Mrs. Jorkins, respectively. Then
h − 1 8 = 3 ( w − 1 8 ) ( 1 )
h = 2 w ( 2 )
Substitutute ( 2 ) in ( 1 ) .
2 w − 1 8 = 3 ( w − 1 8 )
2 w − 1 8 = 3 w − 5 4
w = 3 6
The age of Mrs. Jorkins eighteen years ago was
w − 1 8 = 3 6 − 1 8 = 1 8