Circle Problem

yeah but how do you find the lengths of AE and BE?

A little bit of trigonometry. Let the center of the bigger circle be O, of the smaller circle be P, and angle AOE be β. Let extended AB and OP meet at Q. Then angle BPQ is also β (since OA and PB, being both perpendicular to AQ, are parallel). From similar triangles BPQ and AOQ, we have PQ= $\dfrac{5}{3}$ . Therefore cosβ= $\dfrac{1}{PQ}$ = $\dfrac{3}{5}$ and sinβ= $\dfrac{4}{5}$ . AE=8sin $\dfrac{β}{2}$ = $\dfrac{8}{√5}$ , BE=2cos $\dfrac{β}{2}$ = $\dfrac{4}{√5}$ . Therefore area of the triangle is $\dfrac{1}{2}$ (AE) (BE) = $\dfrac{16}{5}$ =3.2