Absolute problem!

Algebra Level 3

How many integers a satisfy 2 a + 7 + 2 a 1 = 8 \left| 2a+7 \right| +\left| 2a-1 \right| =8 ?

This problem is part of the set Hard Equations

infinite 8 4 5

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3 solutions

Anatoliy Razin
Dec 5, 2014

x = 2a-1 => |x|+|x+8| = 8 => x between -8 and 0 => x in {-7,-5,-3,-1}

Yupp did the same way

Rajat Bisht - 6 years, 4 months ago
Chew-Seong Cheong
Jan 17, 2015

The sure way of solving this problem is plotting out the graphs, as I have done here. The range 3.5 a 0.5 -3.5 \le a \le 0.5 satisfies the equation. Therefore, the number of integers that satisfy the equation is 4 \boxed{4} and they are 3 , 2 , 1 -3,-2,-1 and 0 0 .

Edwin Gray
Sep 11, 2018

The solution in integers is a = 0, -1, -2, and -3. It is worth noting that there are also 5 rational solutions also: 1/2, -1/2, -3/2, -5/2, and -7/2. Ed Gray

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