"Hard" problem?

Algebra Level 1

{ a = b n = 1 a 2 b + 3 a 4 b + . . . + 2017 a 2018 b n = 1 a 2 b + 3 a 4 b + . . . + 201 7 a 201 8 b \begin{cases} a = -b \\ n = 1\sqrt{a} - 2\sqrt{b} + 3\sqrt{a} - 4\sqrt{b} + ... + 2017\sqrt{a} - 2018\sqrt{b} \\ n = 1^a - 2^b + 3^a - 4^b + ... + 2017^a - 2018^b \end{cases}

Enter your answer as the value of n ( a + b ) n(a+b) .

Note: You may use i i to denote 1 \sqrt{-1} midway through your working although your final answer should not contain i i .


The answer is 0.

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1 solution

Math Nerd 1729
Apr 21, 2018

Once you realize that a + b = 0 a+b=0 because a = b a=-b you do not need to think harder anymore.

Good one, Stephen! Almost got me!

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