Hard work or Smart work

We see that 900 is divisible by 25. So the remainder in 901 is 1, 902 is 2, and 903 is 3. Thus we add these remainders to get the total remainder, i.e, 6.

901= 1(mod 25),902=2(mod 25),903=3(mod 25) so the remainder is 1 2 3 (mod 25) = 6.

Mama Use calculator .... :p :p

Since the second digit in all the three numbers is zero, the last two digits of the product will be determined by the last digits of 901, 902 and 903, that is, 1, 2, and 3.So, $901 \times 902 \times 903 = ........06$ The remainder is the same as dividing 6 by 25, i.e.6.

All of us know that 900 is divisible by 25 so the remainder of 901 is 1, 902 is 2, 903 is 3 so you'll add it to get the total remainder

901(mod25)=1 902(mod25)=2 903(mod25)=3 Just add them all up! 1+2+3=6

The unit Digit Will be 06 So The r = 6

its a simple problem on divisibility , 901 902 903 when separately divided by 25 leaves 1 , 2 , 3 as remainder but * is distributed among them so 3 2 1/26 is r=6