Harder Pattern

Logic Level 2

19 20 21 x y 26 28 32 33 40 \boxed{19 \quad 20 \quad 21 \quad x \quad y \quad 26 \quad 28 \quad 32 \quad 33 \quad 40 \quad}

Find product of the values of x x and y y in the pattern above.

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The answer is 528.

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6 solutions

Uahbid Dey
Mar 27, 2015

Mehul Arora
Mar 26, 2015

There are two interwoven sequences.

Starting at 19, alternate numbers progress + 2, +3, +4, +5.

Starting at 20, alternate numbers progress +2, +4, +6, +8.

Q.E.D.

Tariqul Islam
Apr 5, 2015

Here, We have two different sequences.

First Sequence: 19 21 y 28 33

Sequence Sequence: 20 x 26 32 40

First Sequence grows by +2, +3, +4, +5

Second Sequence grows by +2, +4, +6, +8

x = 22 y = 24

So, Product of x and y is (22*24) = 528

Karan Ohri
Apr 6, 2015

If we look towards the question then it consists of two common series.... 1--odd no. elements are: 19 ,21 ,y ,28 ,33---with increase by +2,+3,+4,+5... So, y=21+3=24... 2--even no. element are: 20 ,x ,26 ,32 ,40--with increase by +2,+4,+6,+8... So, x=20+2=22... And x×y=22×24=528

Otto Bretscher
Apr 5, 2015

a n = a n 2 + n 2 a_n=a_{n-2}+n-2 for even n > 2 n>2 and a n = a n 2 + n + 1 2 a_n=a_{n-2}+\frac{n+1}{2} for odd n > 1 n>1 .

Ram Gautam
Apr 5, 2015

Letters! xD

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