Harmonic Series

Calculus Level 1

S = 1 + 1 2 + 1 3 + 1 4 + 1 5 + S = 1 + \dfrac12 + \dfrac13 + \dfrac14 + \dfrac15 + \cdots

Does the above series converges?

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Shiv Kumar
Apr 26, 2016

Relevant wiki: Convergence Tests

By using comparison test

1 + 1 / 2 + ( 1 / 3 + 1 / 4 ) + ( 1 / 5 + 1 / 6 + 1 / 7 + 1 / 8 ) + 1 / 9 + > 1 + 1 / 2 + ( 1 / 4 + 1 / 4 ) + ( 1 / 8 + 1 / 8 + 1 / 8 + 1 / 8 ) + ( 1 / 16 + . 1 / 16 ) + 1+1/2+(1/3+1/4)+(1/5+1/6+1/7+1/8)+1/9 +\cdots > 1+1/2+(1/4+1/4)+(1/8+1/8+1/8+1/8)+(1/16+.\cdots 1/16)+ \cdots

because each term in harmonic series is greater than or equal to to second series.

Now the second series is equal to

1 + 1 / 2 + 1 / 2 + 1 / 2 + 1 / 2 + . 1+1/2+1/2+1/2+1/2+\cdots .

infinite. So harmonic series is also infinite and does not converge .

Jerry Jia
May 13, 2016

Take the harmonic series 1 + 1 2 \frac{1}{2} + 1 3 \frac{1}{3} + ... + 1 x \frac{1}{x} , and apply the integral test on series. After integration, the resultant integral is ln(x). Then we take the limit of the result and we see lim as x -> infinity, ln(x) also approaches infinity. Since the integral does not converge, the harmonic series does not converge.

Ryoha Mitsuya
May 13, 2016

harmonic series diverges - Oresme proof

Hana Wehbi
May 3, 2016

We can look at it 1 n p \frac{1}{n^p} as a p- series, where p is equal to 1, so it diverges.

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...