S = 1 + 2 1 + 3 1 + 4 1 + 5 1 + ⋯
Does the above series converges?
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Take the harmonic series 1 + 2 1 + 3 1 + ... + x 1 , and apply the integral test on series. After integration, the resultant integral is ln(x). Then we take the limit of the result and we see lim as x -> infinity, ln(x) also approaches infinity. Since the integral does not converge, the harmonic series does not converge.
harmonic series diverges - Oresme proof
We can look at it n p 1 as a p- series, where p is equal to 1, so it diverges.
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Relevant wiki: Convergence Tests
By using comparison test
1 + 1 / 2 + ( 1 / 3 + 1 / 4 ) + ( 1 / 5 + 1 / 6 + 1 / 7 + 1 / 8 ) + 1 / 9 + ⋯ > 1 + 1 / 2 + ( 1 / 4 + 1 / 4 ) + ( 1 / 8 + 1 / 8 + 1 / 8 + 1 / 8 ) + ( 1 / 1 6 + . ⋯ 1 / 1 6 ) + ⋯
because each term in harmonic series is greater than or equal to to second series.
Now the second series is equal to
1 + 1 / 2 + 1 / 2 + 1 / 2 + 1 / 2 + ⋯ .
infinite. So harmonic series is also infinite and does not converge .