An algebra problem by om tripathi

Algebra Level 2

Factorize 27 a 3 + 125 b 3 27a^3 + 125b^3 .

( 3 a + 5 b ) ( 9 a 2 + 25 b 2 15 a b ) (3a+5b)(9a^2+25b^2-15ab) ( 3 a 5 b ) ( 9 a 3 5 b 2 18 a b ) (3a-5b)(9a^3-5b^2-18ab) ( 9 a + 25 b ) ( 3 a 2 + 25 b 2 15 a b ) (9a+25b)(3a^2+25b^2-15ab) ( 3 a 25 b ) ( 5 a 2 + 9 b 2 6 a b ) (3a-25b)(5a^2+9b^2-6ab)

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2 solutions

Kay Xspre
Mar 21, 2016

27 a 3 + 125 b 3 = ( 3 a + 5 b ) ( 9 a 2 15 a b + 25 b 2 ) 27a^3+125b^3 = (3a+5b)(9a^2-15ab+25b^2)

Add that : a 3 + b 3 = ( a + b ) ( a 2 a b + b 2 ) a^3+b^3=(a+b)(a^2-ab+b^2)

Department 8 - 5 years, 2 months ago

You didn't add the formula a³ + b³ = (a + b) (a² - ab + b²)

Munem Shahriar - 4 years, 1 month ago
Munem Shahriar
May 14, 2017

27 a 3 + 125 b 3 27a^3 +125b^3

= ( 3 a ) 3 + ( 5 b ) 3 = (3a)^3 + (5b)^3

= ( 3 a + 5 b ) ( 3 a 2 3 a . 5 b + 5 b 2 ) = (3a + 5b)( 3a^2 - 3a . 5b + 5b^2)

= ( 3 a + 5 b ) ( 9 a 2 15 a b + 25 b 2 ) = (3a + 5b) ( 9a^2 - 15ab + 25b^2)

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