Happy birthday Number theory!

Number Theory Level 4

∑ k = 1 n ( 1 f ( k ) f ( k + 1 ) ) = f ( f ( n ) ) f ( n + 1 ) \sum _{ k=1 }^{ n }{ \left( \frac { 1 }{ f(k)f(k+1) } \right) } =\frac { f(f(n)) }{ f(n+1) }

A function f : N → N f : \mathbb {N \to N} satisfies above conditions ∀ n ∈ N \forall n \in \mathbb N .

Find f ( 2017 ) f(2017) .


The answer is 2017.

Priyanshu Mishra by Priyanshu Mishra , 20, India

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1 solution

My way is very long then I Got f(x)=x

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