An algebra problem by Prakhar Singh

Algebra Level pending

If the sum of the n n terms of an arithmetic progression is a n 2 + b n an^2 + bn , find the n th n^\text{th} term of this progression.

b n + a bn + a a n + b an + b 2 a n + b a 2an+b-a a n + b a an+b-a

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1 solution

Prakhar Singh
Feb 12, 2017

S {n} = an^{2} + bn S {n-1} = a( n-1)^{2} + b (n-1) t {n} = S {n} - S_{n-1} = an^{2} + bn -a (n-1)^{2} - b (n-1) = an^{2} - an^{2} + 2an - a + bn - bn + b = 2an - a + b

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