Have you checked your blood sugar yet?

In annual check-up, a standard fasting blood sugar level has a normal range of 75 to 115 mg/dL, claimed to cover approximately 95% of the world's population.

What is the cut-point integer value of high sugar level ( \big( beyond 9 9 th 99^\text{th} percentile ) \big) in an individual? (You don't have to be a doctor to diagnose diabetes.)


The answer is 125.

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1 solution

Relevant wiki: Standard Deviation

In a normal distribution, the data can be pooled with the use of the standard deviation , in this case 95 95 % of the population's data range from 75 75 to 115 115 , which is ± 2 σ \pm 2\sigma from the mean μ \mu .

In other words, 115 = μ + 2 σ 115 = \mu + 2\sigma , and 75 = μ 2 σ 75 = \mu - 2\sigma .

Therefore, μ = 95 \mu = 95 and σ = 10 \sigma = 10 .

To cover 99.7 99.7 % of the world's population, the data will range from μ 3 σ \mu - 3\sigma to μ + 3 σ \mu + 3\sigma or from 65 65 to 125 125 .

Therefore, any value greater than 125 \boxed{125} is considered diabetes.

But is it not beyond 99th percentile that is needed ? Why cover 99.7% of the population ?

Gabin Kolly - 3 years, 2 months ago

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