Suppose you're flying from San Francisco (SFO) to New York (NYC). The plane (Airbus 320) carries 189 passengers and has 6 crew members who each make $20 per hour. Assume a minimal model where the only costs of operating the flight are paying the salary of the crew, and paying for fuel. Further, assume that the all the engine does is fight the drag force. If each ticket costs $300, jet fuel costs $0.75 per liter, and the crew is paid for the number of complete hours they work, what percent of your ticket price goes toward the airline's profit?
Assumptions and Details
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
First of all, the drag force on the plane is given by
F d = 2 1 C d ρ v 2 A
The work done to fight friction in the whole cross-country flight is then
W d = ∫ F d d x = L × 2 1 C d ρ v 2 A
and the total amount of energy we need from the fuel is E fuel = W / η . Plugging all the numbers in, and recognizing A = 9 π , we find that the total amount of energy required is E fuel ≈ 2 . 5 7 7 × 1 0 1 2 Joules.
To get the total amount of fuel we need, we use the density of the fuel, and the energy density of the fuel to convert this into a volume V fuel = E fuel × ρ fuel × 1 0 0 0 L 1 m 3 ≈ 7 1 2 3 9 . 6 L .
The cost of the fuel is thus $ 0 . 7 5 per L × V fuel ≈ $ 5 3 8 9 3 . 4 . The salary of the crew is 6 crew × $ 2 0 per hr × 5 hr , thus the total cost of running the flight is c = $ 5 4 0 2 9 . 7 .
The revenue from operating the flight is simply the ticket price times the number of passengers which is r = $ 3 0 0 × 1 8 9 = 5 6 7 0 0 .
The percent of the ticket prices that goes into profit is thus 1 0 0 × ( 1 − c / r ) = 4 . 7 1 %