Have you ever thought your airline ticket cost too much?

Suppose you're flying from San Francisco (SFO) to New York (NYC). The plane (Airbus 320) carries 189 passengers and has 6 crew members who each make $20 per hour. Assume a minimal model where the only costs of operating the flight are paying the salary of the crew, and paying for fuel. Further, assume that the all the engine does is fight the drag force. If each ticket costs $300, jet fuel costs $0.75 per liter, and the crew is paid for the number of complete hours they work, what percent of your ticket price goes toward the airline's profit?

Assumptions and Details

  • The Airbus has a drag coefficient C D C_D of 1 3 π . \frac{1}{3\pi}.
  • The density of air is ρ = 1.275 kg/m 3 \rho=1.275\text{ kg/m}^3 .
  • The plane flies at 511 mph ( 228 m/s ) 511\text{ mph } (228\text{ m/s}) from start to finish.
  • The distance from NYC to SFO is 4148 km . 4148\text{ km}.
  • The energy efficiency of the jet engines is η = 16 % \eta=16\% .
  • Approximate the Airbus as a cylinder of diameter 6 m . 6\text{ m}.
  • The energy density of the jet fuel is 45 × 1 0 6 J/kg . 45\times 10^6\text{ J/kg}.
  • The density of the fuel is 804 kg/m 3 804\text{ kg/m}^3 .
  • The crew is paid for each full hour they work, i.e. if they work 5.2 hrs 5.2\text{ hrs} they are paid for 5. 5.


The answer is 4.70955.

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1 solution

Josh Silverman Staff
Sep 1, 2015

First of all, the drag force on the plane is given by

F d = 1 2 C d ρ v 2 A F_d = \frac12 C_d \rho v^2 A

The work done to fight friction in the whole cross-country flight is then

W d = F d d x = L × 1 2 C d ρ v 2 A W_d = \int F_d dx = L\times\frac12 C_d \rho v^2 A

and the total amount of energy we need from the fuel is E fuel = W / η E_\text{fuel} = W/\eta . Plugging all the numbers in, and recognizing A = 9 π A = 9\pi , we find that the total amount of energy required is E fuel 2.577 × 1 0 12 E_\text{fuel}\approx 2.577\times10^{12} Joules.

To get the total amount of fuel we need, we use the density of the fuel, and the energy density of the fuel to convert this into a volume V fuel = E fuel × ρ fuel × 1 m 3 1000 L 71239.6 L V_\text{fuel} = E_\text{fuel} \times \rho_\text{fuel} \times \frac{1\text{ m}^3}{1000\text{ L}} \approx 71239.6~\text{ L} .

The cost of the fuel is thus $ 0.75 per L × V fuel $ 53893.4 \$0.75 \text{ per L} \times V_\text{fuel}\approx \$53893.4 . The salary of the crew is 6 crew × $ 20 per hr × 5 hr 6\text{ crew}\times \$20\text{ per hr}\times 5\text{ hr} , thus the total cost of running the flight is c = $ 54029.7 c = \$54029.7 .

The revenue from operating the flight is simply the ticket price times the number of passengers which is r = $ 300 × 189 = 56700 r = \$300\times189=56700 .

The percent of the ticket prices that goes into profit is thus 100 × ( 1 c / r ) = 4.71 % 100\times\left(1 - c/r\right) = 4.71\%

I gave this answer long ago. But I was told I was wrong!

Luciano Riosa - 5 years, 9 months ago

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The problem was recently fixed. I've awarded you your credit.

Brilliant Physics Staff - 5 years, 8 months ago

Dang it! I got everything except for the percentage error formula correct!

Alexander McDowell - 1 year, 2 months ago

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