In a triangle
,
. Points
and
lie on the hypotenuse
such that
and
. Find
in degrees.
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let ∠ B C E = x , ∠ E C F = y and ∠ F C A = z
Now, as B C = B F and also A C = A E
So, ∠ C F E = x + y and ∠ C E F = y + z
Now, y + x + y + y + z = 1 8 0
or, 2 y = 1 8 0 - ( x + y + z ) [x+y+z=90]
so y = 1 8 0 / 2 = 4 5