I have two numbers. The arithmetic mean and the geometric mean of these two numbers are equal. Which of the following is true?
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Let these two numbers be x and you. Setting the two averages equal: (x+y)/2=sqrt (xy) Squaring both sides: (x^2+2xy+y^2)/4=xy Multiplying both sides by four and rearranging terms: x^2-2xy+y^2=0 Factoring and taking thr square root of both sides: x-y=0 This implies that: x=y