Haven't you studied this in 1st grade?

Algebra Level 3

Step 1: We define S= 1 -2+3-4...................

Step 2: See the photo above

Step 3: Adding the four Equations

Step 4: S = 1/4

That's nonsense, bu when I try to figure out where I was wrong I couldn't . Will you do that for me?

I will post the solutions tomorrow. Please visit to see that.

Step 3 Step 2 Step 1 Everyone Knows Step 4 is wrong, So ignore this option.

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2 solutions

All the operations which we learnt in First grade are valid only on convergent series. We can't simply add two divergent series even if they are same. In fact, we can't rearrange the terms also in divergent series. By rearrangement, I mean that in above series we can't rearrange the terms as S= (1+3+5+7...........) - (2+4+6+8...............). If we do so, we can get different answers for different arrangements.

What I have done that I rearranged the terms in sequence and then added them which is not allowed for divergent series.

What I meant when I said that we will get different answer for different arrangements:

In question, we have seen that answer is 1/4. Focus on the sequence given in solution above.

Sum of odd numbers upto n is n^2 and sum of even number upto n is n(n+1). If I substitute this value in above equation, I get

S=n^2 - n(n+1) = -n

As n is tending to infinity, I get the answer as -(infinity)

But, now the question arises, what's the exact value of S. We can't tell the exact value, But by carefully analysing the series, we see that each positive term is succeeded by a negative terms whose magnitude is greater than positive term, So the answer is -(infinity). Since, we can conclude nothing about infinity, we say that the series diverges over R.

I'd disagree with you.

We define S= 1 -2+3-4................... We define S as something that doesn't converge i.e. we define S as something that doesn't exist... Answer should be Steps 1 and 4 were wrong

Karan Pedja - 6 years, 5 months ago

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What's wrong in defining a variable. However, If I defined a function, then assigned S to that function, then S will not be defined if the function diverges for a given value of x. The reason is that since the function is not defined, hence S will not be defined.

I can define S=(a harmonic series) which generally diverges.

Haven't you seen examples like : k=tan(x) where x belongs [o,pi]. Here, since tan(x) is not defined for (pi/2), hence k is not defined for pi/2.

If you have any confusions then refer: http://en.wikipedia.org/wiki/1 %E2%88%92 2 %2B 3 %E2%88%92 4 %2B %E2%8B%AF

Prakash Chandra Rai - 6 years, 5 months ago
Kaushik Venkatesh
Dec 28, 2014

If you think this looks absurd.. Then how would you react to this... 1+2+3+4. ........=-1/12 think about it!;)

i know it's proof but i want to ask you the proof is right or wrong

kanishk arora - 6 years, 5 months ago

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Can you post the proof?

Prakash Chandra Rai - 6 years, 5 months ago

obviously wrong, it is also a divergent series. I don't know much and may be I am wrong but it was one of the rarest mistakes done by Ramanujan which he corrected afterwards

Prakash Chandra Rai - 6 years, 5 months ago

I have seen the proof. Again in that proof they have multiplied it by 4 which you can't do for divergent series.

For infinite series, we must be very careful. Not only in divergent series,but also in some(very few) of convergent series, rearrangement is not allowed, I am posting an article from Wikipedia:

"Generally speaking, it is dangerous to manipulate infinite series as if they were finite sums, and it is especially dangerous for divergent series. If zeroes are inserted into arbitrary positions of a divergent series, it is possible to arrive at results that are not self-consistent, let alone consistent with other methods."

Prakash Chandra Rai - 6 years, 5 months ago

Unfortunately this isn't exactly correct. More precisely, 1 12 -\frac{1}{12} is a hypothetical sum given by hypothetical methods such as ζ ( 1 ) \zeta (-1) or the Ramanujan method. The sum of the natural numbers is still divergent, and very divergent at that.

Caleb Townsend - 6 years, 3 months ago

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You won't believe but modern physics theories like string theory use this result in countless proofs and topics.

Prakash Chandra Rai - 6 years, 1 month ago

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