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Algebra Level 4

Cards are numbered between 31 to 81 exclusive. If the sum of the probabilities of getting a card number divisible by 2, a perfect square, a card number divisible by 3,a card number multiple of 9 a card number multiple of 45 and a card number multiple of 81 is written as A/B. Then what is the value of A+B???


The answer is 99.

Hrishikesh Dani by Hrishikesh Dani , 23, India

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1 solution

Hrishikesh Dani
Feb 27, 2014

Total possible outcomes are 81-31-1 because between is given are 49. Therefore 1st probability is 24/49 then next is 3/49 then next is 16/49 next is 1/49 and last is 0/49. Thus all adds up to 1. Therefore A=1, B=1 and A+B=2. Thus solution is 2

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the 1st probability of numbers divisible by 2 should be 25/49 and not 24/49. the answer should be 99

kaustubh porlikar - 7 years, 2 months ago

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I have updated the answer to 99.

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Calvin Lin Staff - 6 years, 11 months ago

It should be specified that 31 and 81 are excluded.

Aloysius Ng - 7 years ago

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Rght ...i got it wrong due to that !!!!! *repression !

Apoorv Padghan - 6 years, 10 months ago

1st probablity is 25/49 .. so A/B = 50 / 49 .. therefore , A+B = 50+49 = 99

Anand O R - 7 years, 2 months ago

Your language are quite strange! The word "BETWEEN" stand for ONLY the objects inside the gap, 31 and 81 must be taken away.

Krit Phuengphan - 7 years ago

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By the way, the answer is 99

Krit Phuengphan - 7 years ago

Thanks. I've updated the question and added the word "exclusive".

Calvin Lin Staff - 7 years ago

If there are 49 numbers,the first of which is an even integer, then no. of even integers=50/2= 25 .thus A/B =50/49...and in your solution,you have not only written the 1st probability wrong but you have also missed the multiples of 9...My rating decreased unnecessarily :(

Varenya Srivastava - 6 years, 12 months ago

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