Head's in Three's

A person tosses a fair coin n n times , he wins if he is able to get heads in a multiple of 3. The probability of the person winning if it is given that he gets head at-least one time (given that n n is not a multiple of 3) is

1 3 \frac{1}{3} 2 n 4 3 × ( 2 n 1 ) \frac{2^{n}-4}{3\times(2^{n}-1)} none of these 2 n 4 3 × 2 n \frac{2^{n}-4}{3\times2^{n}}

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