Heat and Thermo

In an adiabatic expansion of air the volume increases by 5%. Then the percentage change in pressure is __%.


Note: If the pressure decreased, then the percentage change will be negative.


The answer is -6.6.

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1 solution

Gediminas Sadzius
Feb 19, 2021

Assuming the air is at low pressure, the following polytropic process equation holds:

P 1 V k 1 = P 2 V k 2 P_1 V^k{}_1=P_2 V^k{}_2

Where subscript "1" is the state before and "2" after the change took place. "P" is pressure, "V" is volume and "k" is ratio of specific heats. For air at low pressure (approx. ideal gas):

k = 7 5 k=\frac{7}{5}

The volume of the air has increased by 5%, so:

V 2 = 1.05 V 1 V_2=1.05 V_1

After plugging this into the first equation above and simplifying:

P 1 = 1.0 5 k P 2 P_1=1.05^k P_2

So:

P 2 P 1 P 1 = 1 1.0 5 k 1.0 5 k \frac{P_2-P_1}{P_1}=\frac{1-1.05^k}{1.05^k}

or -0.066 x 100% = 6.6 % \boxed{-6.6\%}

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