Heave ho

Mass of basket( $m_{basket}$ ) = $100kg$

Acceleration due to gravity( $g$ ) = $-9.8ms^{-2}$

So, force exerted by basket( $F_{basket}$ ) = $m_{basket} \times g = 100 kg \times (-9.8 ms^{-2})=-980 N$ in downward direction.

So, to counter this force and prevent the basket from plunging into the water, we have to apply a force at least $980N$ in magnitude in the upward direction. So, amount of force we have to apply is:

$F_{we apply}=\boxed{980N}$ in upward direction.

We know that $N = kg.m/s^{2}$

Here total mass = $100kg$

And the acceleration working on the basket due to gravity = $9.8m/s^{2}$

And the total force in Newtons is = $N \implies 100 \times 9.8 \implies \boxed{980 kg.m/s^2 or N}$

its simple.

100 kg X 9.8 m/s^2 = 980 N

1. Information about the question : $m = 100 kg$ , $g = 9.8 m/s^2$ .
2. Now, you will need to put in the formula. $F = m*a$
3. $F = 100 * 9.8$ = $\boxed{980}$

by newton's second law of motion f=ma 100(9.8) =980 like a boss.