Height Problem 2

Algebra Level 3

R is 156 cm tall.S is one sixth × \times 8 of R. P is 1 4 t h \cfrac { 1 }{ 4 } th of S × \times 5 2 \cfrac { 5 }{ 2 } .And Q is 1 5 t h \cfrac { 1 }{ 5 } th\quad of P × 4 \times \quad 4

Then add their heights , add 2 in that addition , and then square the solution after adding 2, and write the answer.


The answer is 360000.

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1 solution

Anshul Sharma
Sep 26, 2014

simple one R's Height =156 cm
S's Height =8 x (1/6) x 156 =208 cm P's height =1/4 of S x 2=(1/4) x 208 x (5/2) =130 cm similar way find Q's height i.e.104 cm ON ADDING - 156+208+130+104=598 then add 2 598+2=600 then squaring (600)^2=360000 That's all..................

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