Height Problem

R > P.

S > R.

N > R.

N > S.

N > P.

T > N.

T > P.

Legend:

> = Taller. So.

5 numbers.

N > R

N > S

N > P

N is established to be the second number.

T > N

T > P

If T is superior to N, which is superior to everything else, it would make sense that T is first. T > P is just a distraction.

R > P

S > R

So, S would secure a spot at third place, R would secure one at fourth, and P would secure the last spot.

Thanks for taking the time to read this.

The sequence is T,N,S,R,P therefore R Is the answer

R is taller than P but shorter than S and N.so, $S,N>R>P$

N is greater than S and P , but lesser than T.so, $T>N>S>R>P$

so,R will come to the 4th position.

1. R is taller than P. We will start off with R P
2. R is shorter than S and N though. We now have S N R P
3. N is taller than S and P. N S R P
4. T is taller than N. T N S R P The answer is R

T > N > S > R >P Cuarta posición: R

TNSRP... so R.

Descending order- T-N-S-R-P , its "R"

We know: R > P; R < S; R <N. and N > S; N > P; N < T. and T > P. So, S > R > P e N > R > P. and T > N > P e T > N > S. Thus we can find: T > N > S > R > P. Therefore, the 4th one is "R".

With the given statements in the problem we have:

Given: Implication: R>P which is P<R R<S which is S>R R<N which is N>R N>S which is S<N N>P which is P<N N<T which is T>N T>P which is P<T

With that given statements and their implications we can now rank their heights with descending order: T,N.S,R,P

S&N>R>P,T>N>S&P, T>N>S>R>P

S&N>R>P T>N>S&P T>P descending order T>N>S>R>P

T, N, S, R <-, P

let r be the highest

arrangement: r

R is taller than P but shorter than S and N

arrangement: s/n r p

N is greater than S and P , but lesser than T

arrangement: t n s r p

T is greater than P

final arrangement: t n s r p

4th place: r

"R is taller than P but shorter than S and N."

We know from this order, that P is the shortest, followed by R, but we do not know which is taller of S and N. [ P R ? ? ]

"N is greater than S and P, but lesser than T, and T is greater than P."

We now need to add T, but we now know N is taller than S. We also know T is taller than N, making T our tallest. Rework our list: [ P R S N T ]

"If we arrange their heights in descending order, who will come to the 4th position?" By reversing our list (making it descending, and not ascending), we get: [ T N S R P ] ; and we can see that the 4th element is R. R is our answer.

At first R is shorter than N and S.Then we come to know that N is greater compared to S and also T is greater than N.hence the order is,

1)T 2)N 3)S 4)R 5)P

hence,the fourth position is R.

as we arrange this sequence T>N>S>R>P in this way we get R on 4th position

1.1: R > P; R < S; R <N.

1.2: N > S; N > P; N < T.

1.3: T > P.

2.1: S > R > P e N > R > P.

2.2: T > N > P e T > N > S.

So, you can see:

T > N > S > R > P.

The 4th is "R". Doubts? Ask!

Descending Order T>N>S>R>P

1.R>P>S,N 2.T>N>S, P 3.T>P so, S, P>R

The arrangement is T>N>S, P>R(4rt position)