Try This Logic Problem

Let the $n$ th term of the sequence be $a_n$ . Then the $(n+1)$ th term is given by $a_{n+1} = a_n + s_n$ , where $s_n$ is the digital sum of $a_n$ . The sequence actually starts with $a_0 = 31$ , then $a_1 = 31+4 = 35$ , $a_2 = 43$ , $a_3=50$ , $a_4 = 55$ , $a_5 = \boxed{65}$ , $a_6 = 76$ , ....