Find the area of a triangle with side lengths 2, 3 and 4.
Give your answer to 1 decimal place.
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Heron's formula is
S = 2 a + b + c
and the area is
A = S ( S − a ) ( S − b ) ( S − c )
With a triangle sides 2, 3, and 4, S = 2 2 + 3 + 4 = 4 . 5 . When S = 4 . 5 , the area would be
A = 4 . 5 ( 4 . 5 − 2 ) ( 4 . 5 − 3 ) ( 4 . 5 − 4 ) = 4 . 5 ∗ 2 . 5 ∗ 1 . 5 ∗ 0 . 5 = 8 . 4 3 7 5 ≈ 2 . 9 .