Hexadecimal Equations (Problem $2$ , Version $2$ )

$E = 14$

$2 \times 16^1 = 32 + 14 = 46$

$6 \times 16^1 = 96 + 14 = 110$

$1 \times 16^2 + 9 \times 16^1 = 1 \times 256 + 9 \times 16 = 256 + 144 = 400 + 14 = 414$

$46 + 110 + 414$

$110 + 460$

$570$

Answer $\rightarrow \fbox{570}$

For the Bonus:

$570$

Do division by $16$ to get the L.H.S of the modulo calculations.

$570 (\text{mod}(16)) = 10$

$35 (\text{mod}(16)) = 3$

$2 (\text{mod}(16)) = 2$

Read from bottom to top:

$2310$

Since $10 = A$ :

$23A$

Bonus Answer $\rightarrow 23A$