Hidden Algebra?

Is there any positive integer greater than 2, such that the number of positive factors of the integer is equal to the integer itself?

Yes No

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1 solution

Henry U
Nov 12, 2018

For this to be true, the integer would have to be divisible by all natural numbers less than or equal to it. This can't be the case since no integer n n (except 2 and 0, maybe) is divisible by n 1 n-1 . Therefore the answer is No .

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