High school calc problem

Calculus Level 3

Slope of the tanget to the curve *X= y^100 + log (100)^y * at the point (0,0) equal ...


The answer is 0.5.

Ahmed Mahmoud by Ahmed Mahmoud , 20, Egypt

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1 solution

dx/dy=log100=2. Therefore dy/dx=1/2=0.5

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How did you get that dx/dy=log100? can you clarify it with more steps?

Ahmed Mahmoud - 2 years, 2 months ago

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Differentiate both sides of the equation with respect to y and put y=0

A Former Brilliant Member - 2 years, 2 months ago

Assuming the equation reads x = y 100 + log ⁡ 100 y x= y^{100} + \log_{100} y .

The curve doesn't pass through the point ( 0 , 0 ) (0,0) , so this question is impossible to solve. Which makes your solution wrong.

Pi Han Goh - 2 years, 2 months ago

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It's not log of y to the base 100, but log of 100^y to the base 10

A Former Brilliant Member - 2 years, 2 months ago

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