If I have 3 dice, which of the following probabilities is not equal to the probability of rolling a pair of sixes with two dice?
A) With 3 dice, rolling any triple (i.e. 1, 1, 1)
B) With 3 dice, rolling to get a sum of 16
C) With 3 dice, rolling two equal numbers and a differing one (i.e. 1, 2, 1)
D) With 3 dice, rolling to get a sum of 5
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The probability of rolling a pair of sixes with two dice is 3 6 1
Including permutations, there are 216 different outcomes of rolling 3 dice and we'll use this to compare the outcomes:
There are only 6 possible triples that can be rolled with three dice and 2 1 6 6 is equal to 3 6 1
With 16 there are again only 6 ways to roll:
4, 6, 6
5, 5, 6
5, 6, 5
6, 4, 6
6, 5, 5
6, 6, 4
And with 5 there are also only 6 ways to roll:
1, 1, 3
1, 2, 2
1, 3, 1
2, 1, 2
2, 2, 1
3, 1, 1
When it comes to C, though, there are 60 different possibilities which I can't list here but is provable: Once you have rolled your first number i.e. 5, there are two ways to get this type of roll, either a) the next two numbers are a double, excluding 5, which gives 5 possibilities, or b) the next two numbers are different and one of them is a 5, which gives another 5 possibilities. Together these make 10, and if you multiply these results by 6 then you have 60.