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Geometry Level 3

If cot θ 1 cos 2 θ = 1 \cot \theta \ \sqrt{1 - \cos^2\theta} = 1 and θ = [ 0 , 36 0 ) \theta = [0^\circ,360^\circ)

Find the solution set of θ \theta .

x = {0} x = {90,270} x = {90} x = {0,180} None of the choices x = {180} x={270}

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1 solution

Paul Ryan Longhas
Apr 29, 2015

Since, cot θ 1 cos 2 θ = 1 cot θ sin θ = 1 \cot \theta \sqrt{1-\cos^2\theta} = 1 \Rightarrow \cot \theta|\sin\theta| = 1

cos θ = 1 \Rightarrow \cos \theta = 1 or cos θ = 1 \cos \theta = -1

So, sin θ = 0 \sin \theta = 0

But if sin θ = 0 cot θ \sin \theta = 0 \Rightarrow \cot\theta is undefined.

So, the answer is "None of the choices".

Arghhhhh! you got me!Nice problem

Arian Tashakkor - 6 years, 1 month ago

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This problem reminded me to remember the basics :)

Aditya Garg - 6 years, 1 month ago

Ah! JEE standards !!

Abhishek Singh - 6 years ago

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