HIT THE BALL & THE ROD!!

A rod of mass m m & \& length l l is hinged at one end O O .A particle of mass m m travelling with speed v v collides with the rod at a distance x x from the centre of mass of the rod such that the reaction force at the hinge is 0 0 .Then if x x = l α \frac{l}{\alpha} ,evaluate α \alpha .

Five identical balls each of mass m m & \& radius r r are stung like beads at random and at rest along a smooth,rigid horizontal thin rod of length L L ,mounted between immovable supports.Assume 10 r < L 10r<L and that the collison between balls or between balls and the support are elastic.If one ball is stuck horizontally so as to acquire a speed v v ,the magnitude of the average force felt by the support is β m v 2 L σ r \frac{\beta*m*v^2}{L-\sigma*r} Evaluate β \beta and σ \sigma .

Find α + β + σ \alpha+\beta+\sigma


The answer is 17.

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1 solution

Rajdeep Brahma
Jun 26, 2018

Relevant wiki: Conservation of Momentum

So in problem 1 linear momentum and angular momentum about hinge both are conserved.Let after collison the speed of the ball be u 1 u_1 and that of rod be u 2 u_2 .Conserving momentum we get v v = u 1 + u 2 u_1+u_2 .Now conserve angular momentum about O O .We will get that v ( x + l 2 ) = u 1 ( x + l 2 ) + u 2 2 l 3 v*(x+\frac{l}{2})=u_1*(x+\frac{l}{2})+u_2*\frac{2l}{3} .Which will eventually yield x = l 6 x=\frac{l}{6} .

In problem 2,we know F= d P d t \frac{dP}{dt} ,since the collisons are all elastic,when one ball with velocity v v hits the other it itself stops and the ball it had hit moves with velocity v v .So d P = 2 m v dP=2mv and d t = 2 ( L 10 R ) v ) dt=\frac{2*(L-10*R)}{v}) and so F= m v 2 L 10 r \frac{mv^2}{L-10*r}

NOTE: BOTH OF THEM ARE INPHO 2009 PROBLEMS.SO NO CLAIM OF ORIGINALITY IS MADE.

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