Hitchhiking Through The Galaxy

Algebra Level 2

During one of my summer vacations, I was hitchhiking down Route 1. I happened to notice this globe just sitting out there. Upon further investigation, I learnt that the largest complete scale model of the solar system is in Aroostook County, Maine, U.S.A. The model extends along Route 1 with a 15 m model of the sun at one end and a 2.5 cm model of Pluto 64 km away. On this scale, what should the diameter of the model of Jupiter be, given that its actual diameter is 138350 km?

Note: For reference, Pluto's actual distance from the Sun is approximately 5.95 × 1 0 12 5.95 \times 10^{12} m, and the sun's actual diameter is approximately 1.39 × 1 0 9 1.39 \times 10^9 m.

Image Credit: Michael York
0.64 m 0.15 m 6.4 m 1.5 m

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6 solutions

Lakshya Gupta
Mar 11, 2014

Be solving, we get that diameter of Jupiter is about 0.139 x 10^9m, which is 1/10th that of the sun, so in the model, the diameter of Jupiter will be 1/10th that of the Sun, that is 1.5m

Yeah

Kahsay Merkeb - 7 years, 3 months ago

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correcto!

A Former Brilliant Member - 7 years, 3 months ago

0.139x10^8

Suresh Visweswara - 7 years, 3 months ago
Joe Lingle
Mar 18, 2014

138350 : 1390000 = x : 15 therefore x = 1.5

Tasnim Rawat
Mar 21, 2014

convert the distance between sun and Pluto i.e 5.95 * 10 ^ 12 m = 64 km

so 5.95 * 10 ^ 12 m = 64000 m

1 m = 92968750 m

now radius of sun = 1.39 * 10 ^ 9 m = 15 m

15 m = 1.39 * 10 ^ 9 m

1 m = 92666666 m

By this diameter of Jupiter model can be 138350000/92968750 = 1.488 =1.5 m

138350000/92666666 = 1.49 = 1.5 m

Mahendar Singh
Mar 20, 2014

15: (1.39 X 10 ^6) = x: (0.139 X 10^6)

Simple ratio

Laxman Selvam
Mar 16, 2014

the jupiter's dia is 1/10th of the sun's. and hence even in the model the ration would be the same and hence the dia of jupiter's model would be 1.5m

Hussain Syed
Mar 12, 2014

If you check, you will find that Jupiter's diameter is one-tenth that of sun. Applying the same scale, it is 1.5 m

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