IS THE FOLLOWING TRUE?
x^4 + x^3 + x^2 + x + 1 | x^44 + x^33 + x^22 + x^11 + 1.
WHERE ' | ' MEANS COMPLETELY DIVISIBLE WITH.
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hint is try using complex number route, job will be done before u even know
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Thanks for the hint! I got it! Is there any more method?
So setting x 4 4 + x 3 3 + x 2 2 + x 1 1 + 1 = p ( x ) ( x 4 + x 3 + x 2 + x 1 + 1 ) + q ( x ) where de g ( q ( x ) ) ≤ 3 or q ( x ) = 0 . Let x 4 + x 3 + x 2 + x 1 + 1 = 0 So we get x 5 = 1 . Then substituting in the original equation, we get q ( x ) = 0 .
Thank you @Ruchir Singh
nice dude @Vinayak Srivastava
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