Hollow rectangle at the edge!

Classical Mechanics Level 3

A rectangular frame of a uniform density is placed on a table so that its edges are parallel to the table's edges, and only one corner of the frame is on the table. Let A A be the area contained by the frame that is not over the table, and let B B be the area contained by the frame that is over the table.

What is the maximum ratio of area A B \frac{A}{B} for which the frame will not fall off the table?


The answer is 0.

Kelvin Hong by Kelvin Hong , 21, Malaysia

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1 solution

Kelvin Hong
Aug 27, 2017

When the frame is just going to fall down, XY will be its axis of rotation.

When A A has area not equals to 0, the frame will straight forward going down but not just going to fall.

So A B = 0 \frac{A}{B}= \boxed{0}

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