Atmospheric physics 2: Homogeneous atmosphere

Suppose that air was an incompressible fluid. In this case, there would be a sharp interface between the earth's atmosphere and space at an altitude of z 0 z_0 above the ground. Below this interface, the mass density of the air would be constant, i.e. ρ ( z ) = ρ 0 . \rho(z) = \rho_0.

How does the air pressure P ( z ) P(z) in this case depend on the altitude z ? z?

Choose the plot in the diagram below that best describes the physical relation for the homogeneous atmosphere.

Note: The thickness z 0 z_0 of the atmosphere is small in comparison with the earth's radius, so that the curvature of the earth can be neglected. In addition, the gravitational acceleration within the atmosphere is constant.

(a) Quadratic decrease (b) Exponential decrease (c) Linear decrease (d) Step function

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1 solution

Markus Michelmann
Feb 22, 2018

The air pressure P ( z ) P(z) at altitude z z corresponds to the weight F = m ( z ) g F = m(z) g of the overlying atmospheric layers. The partial mass m ( z ) m(z) is obtained by integrating the air density ρ ( z ) \rho(z) over the volume between the altitudes z z and z 0 z_0 : m ( z ) = z ρ ( z ) A d z = z z 0 ρ 0 A d z = ρ 0 A ( z 0 z ) P ( z ) = m ( z ) g A = ρ 0 g ( z 0 z ) = P 0 ( 1 z z 0 ) \begin{aligned} m(z) &= \int_{z}^{\infty} \rho(z') \cdot A dz' = \int_{z}^{z_0} \rho_0 \cdot A dz' = \rho_0 A (z_0 - z) \\ \Rightarrow \quad P(z) &= \frac{m(z) g}{A} = \rho_0 g (z_0 - z) = P_0 \left(1 - \frac{z}{z_0}\right) \end{aligned} Here, the pressure decreases linearly with the altitude and becomes zero at the interface to space (comparable to the hydrostatic pressure of water).

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