The average of 10 numbers is 10. If a number is excluded from this set, then the new average becomes 9.
What is the value of the number that was excluded?
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Relevant wiki: Mean (Average)
We have ( x 1 + x 2 + x 3 + ⋯ + x 1 0 ) / 1 0 = 1 0 .
Lets say x 1 + x 2 + ⋯ x 1 0 = S .
So S = 1 0 0 , and let S ′ denote the sum of the nine remaining numbers.
So S ′ / 9 = 9 , or S ′ = 8 1 .
And S = 1 0 0 . So S − S ′ = 1 9 . So the excluded number is 1 9 .