You want to maximize the odds of obtaining exactly 2 heads in a coin toss.
Would you rather toss 4 fair coins, or 4 identically biased coins?
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If we assume, that all 4 coins are identical (either all fair or all of them are biased the very same way), then the probability of getting exactly 2 coins can be modeled by using the binomial distribution:
P r ( X = 2 ) = ( 2 4 ) × p 2 × ( 1 − p ) 2 = 6 p 2 ( 1 − p ) 2 ,
where p is the probability of getting a head when tossing any (1) of the coins.
Due to the AM - GM inequality,
p 2 ( 1 − p ) 2
is maximal when
p = 1 − p ⟺ 2 p = 1 ⟺ p = 0 . 5 ,
which is the p value of a fair coin.
Therefore, in order to maximise our odds, we should:
Toss 4 fair coins.