How Bias Is Bias?

You want to maximize the odds of obtaining exactly 2 heads in a coin toss.

Would you rather toss 4 fair coins, or 4 identically biased coins?

Toss 4 biased coins There is insufficient information Toss 4 fair coins

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1 solution

Zee Ell
Aug 20, 2016

If we assume, that all 4 coins are identical (either all fair or all of them are biased the very same way), then the probability of getting exactly 2 coins can be modeled by using the binomial distribution:

P r ( X = 2 ) = ( 4 2 ) × p 2 × ( 1 p ) 2 = 6 p 2 ( 1 p ) 2 Pr(X = 2) = {4 \choose 2} × p^2 × (1 - p)^2 = 6p^2(1- p)^2 ,

where p is the probability of getting a head when tossing any (1) of the coins.

Due to the AM - GM inequality,

p 2 ( 1 p ) 2 p^2(1- p)^2

is maximal when

p = 1 p 2 p = 1 p = 0.5 , p = 1 - p \iff 2p = 1 \iff p = 0.5 ,

which is the p value of a fair coin.

Therefore, in order to maximise our odds, we should:

Toss 4 fair coins. \boxed { \text {Toss 4 fair coins.} }

A simpler way to maximize f ( p ) = p 2 ( 1 p ) 2 f(p) = p^2 (1 - p)^2 in the interval 0 < p < 1 0< p < 1 is equivalent to maximizing the parabola g ( p ) = f ( p ) = p ( 1 p ) g(p) = \sqrt{f(p)} = p (1-p) . So there isn't a need to use AM GM.

Pi Han Goh - 4 years, 9 months ago

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