r of the largest circle that can fit into one of the corners?
A circle of radius x is inscribed in a square. What is the radiusState the radius as r = x ( a + b c ) where a , b , c , are integers and c is not divisible by the square of any prime. Find a + b + c .
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I'm disappointed that there weren't more attempts at this problem. Its solution is comparatively easy. I was leading up to a similar case but in 3 dimensions which would really challenge you.
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Have you posted the 3-dimensions case? If so, you should link it.
Looking 4wrd to d 3D problem.By the way how about generalizing this problem for the nth corner circle.Can it be done?
I did the same way..
a = 3 , b = − 1 , c = 8 is also a valid answer, so maybe you should specify b , c as coprime.
Equating the 2 formulas for half of the diagonal of the square: x 2 + x 2 x 2 x ( 2 − 1 ) r r r r r = x + r + r 2 + r 2 = x + r + r 2 = r ( 1 + 2 ) = x ( 2 + 1 ) ( 2 − 1 ) = x ( 2 + 1 ) ( 2 − 1 ) ( 2 − 1 ) ( 2 − 1 ) = x 2 − 1 2 − 2 2 + 1 = x ( 3 − 2 2 ) = x ( a + b c ) , a = 3 , b = − 2 , c = 2
Thus, a + b + c = 3 − 2 + 2 = 3
completely wrong concept
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Can you elaborate, in what sense is this a "completely wrong concept"?
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title <br>a+b+c= 3+(-2)+2 = 3