A sonar transmitter operates at 2 impulse per second. if the device is held to the surface of fresh water (Eb=2.04E9 Pa) and the echo is received midway between impulses , how deep is the water in meter?
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Sonic velocity expressed as: c=sqrt(E/p) = sqrt(2.04E9/1000)= 1428 m/s since the echo is received midway between impulses, then the total time of travel of sound t=1/2(.5) = 0.25 and the distance covered is 2h then. 2h=ct 2h=1428(0.25) h=178.5 m