How Do I Ordinate?

Algebra Level 3

A = 2017 + 13 2 2017 + 13 B = 2017 + 14 2 2017 + 14 C = 2017 + 15 2 2017 + 15 \begin{matrix} A = \dfrac{2017+13}{2^{2017}+13}\\ \\ B = \dfrac{2017+14}{2^{2017}+14}\\ \\ C = \dfrac{2017+15}{2^{2017}+15} \end{matrix}

A > B > C A > B > C A < B < C A < B < C A = B = C A = B = C

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1 solution

Tom Engelsman
Mar 27, 2018

We have a case of:

A = x y , B = x + 1 y + 1 , C = x + 2 y + 2 A = \frac{x}{y}, B = \frac{x+1}{y+1}, C = \frac{x+2}{y+2}

where x < y x < y . Taking the example x = 1 , y = 2 x = 1, y = 2 , we obtain:

1 2 < 2 3 < 3 4 \frac{1}{2} < \frac{2}{3} < \frac{3}{4}

Hence by the same reasoning for x = 2017 + 13 , y = 2 2017 + 13 x = 2017 + 13, y = 2^{2017} + 13 , we finally obtain A < B < C . \boxed{A < B < C}.

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