This problem’s question:
How do the rectangles' areas compare?
The construction:
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ABCD is the given rectangle.
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Extend AB (green in the illustration).
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Make an arc centered on B from C to where it encounters the AB (green) line. Label the intersection E.
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Construct a perpendicular bisector between A and E. This is the two orange arcs of the same but not specific radius, the points where the two arcs intersect labeled P and Q and then draw a straight line (purple in the illustration) between P and Q to intersect AE. Label that last intersection M.
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Draw a circle (green in the illustration) of radius ME centered at M.
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Extend side CB this line is blue in the intersection) to where it intersects the previous circle. Label this point F.
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Draw a arc (dashed black in the illustration) of radius BF centered at B to where it intersects the AE extension. Label this point G.
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Draw a arc (dashed red in the illustration) of radius BG centered at G to where it intersects the AE extension.
Draw a arc (also dashed red in the illustration) of radius FB centered at F to where it intersects the previous arc. Label this point H.
The new rectangle is BFHG and by construction, it is square.
See Rectangle Squaring . The areas are equal.