How far is the ant from its position?

Geometry Level pending

The coordinates of ant H and ant K are (-16,18) and (4,2) respectively. Both ants move towards each other on a straight line with different velocities. The velocity of ant H is 3 times the velocity of ant K. What is the distance of ant H from its initial position when it meets with ant K.


The answer is 19.21.

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1 solution

Ming Xian
Aug 10, 2018

Since ant H travels 3 times faster than ant K,then the distance covered by ant H is 3 times the distance travel by ant K.

Hence,when both ants meet with each others the ratio distance of ant H to ant K is 3:1. Thus, the equation will be ( 12 16 4 \frac{12-16}{4} , 6 + 18 4 \frac{6+18}{4} ) =(-1,6)

The ants will meet with each other at point (-1,6). Then use the equation of calculating distance to calculate the distance of ant H d(squared)=225+144, d(squared)=369, d=19.21 units

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