If the payoff for Newcomb's problem is as listed above, then what is the probability of Omega guessing correctly at which the expected payoff for choosing only box is equal to the expected payoff for choosing both boxes?
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So we have to resolve:
1,000,000 × p + (1 - p) × 0 = 1,000 × p + (1 - p) × 1,001,000
And the solution is p = 0.5005